Determine the reactions on the beam

Determine the reactions on the beam shown

→+ΣFx = 0

Ax - 270cos60° = 0
Ax = 135 KN

↻+ΣM_A = 0

270sin60° (3) - 270cos60° (0.3) + 6.8 - By(4.2) = 0

By = 159 KN

↻+ΣM_B = 0

Ay(4.2) - 270sin60° (1.2) - 270cos60° (0.3) + 6.8 = 0

Ay = 74.8 KN

or

 ↑+ΣFy = 0

Ay - 270sin60° + 159 = 0

Ay = 74.8 KN

Ans.
Ax = 135 KN
By = 159 KN
Ay = 74.8 KN